=>\(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{x}-\frac{1}{x+1}=\frac{10}{11}\)
=>\(1-\frac{1}{x+1}=\frac{10}{11}\)
=>\(\frac{1}{x+1}=1-\frac{10}{11}\)
=>\(\frac{1}{x+1}=\frac{1}{11}\)
=>x+1=11
=>x=10
[1/1.2+1/2.3+1/3.4+..............+1/19.20];x=9/10
tìm x trong biểu thức sau
(1/1.2=1/2.3+1/3.4+.....+1/8.9=1/9.10).100-[5/2:(x+206/100)]:1/2=89
Tìm x , biết :
1/1.2 + 1/2.3 + 1/3.4 + 1/4.5 + ....... + 1/x.(x + 1) = 2018/2019
Giúp em nha !
Tìm x biết: \(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{\left(x-1\right)\times x}=\frac{15}{16}\)
Tìm x
5/1.2 + 5/2.3 + 5/3.4 + .... + 5/x.(x + 1) = 64/13
a, 1313/1212:x=1/1.2+1/2.3+1/3.4+1/4.5+1/5.6
a, 1313/1212:x=1/1.2+1/2.3+1/3.4+1/4.5+1/5.6
Tìm x
x - \(\left(\frac{1}{1.2}-\frac{1}{2.3}-\frac{1}{3.4}-...-\frac{1}{98.99}-\frac{1}{99.100}\right)=\frac{1}{100}\)
Tìm x,biết:
(\(\dfrac{1}{1.2}\) + \(\dfrac{1}{2.3}\) + \(\dfrac{1}{3.4}\) + ........ + \(\dfrac{1}{8.9}\) + \(\dfrac{1}{9.10}\)) . 100 - [ \(\dfrac{5}{2}\) : (\(x+\dfrac{206}{100}\)) ] : \(\dfrac{1}{2}\) = 89
(Dấu . trong bài là dấu nhân ạ)
