\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{99}-\frac{1}{100}\)
= \(=1-\frac{1}{100}\)
\(\frac{99}{100}\)
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Các câu hỏi tương tự
(2+4+6+...+100) - (1+3+5+...+99) = ?
1 x 2 + 2 x 3 + 3 x 4 + ... + 99 x 100 = ?
3 x 4 + 4 x 5 + 5 x 6 + ... + 149 x 150 = ?
1 + (1 + 2) + ( 1 + 2 + 3) + (1 + 2 + 3 + 4) + ....... + (1 + 2 + 3 + ... + 99)
----------------------------------------------------------------------------------------------------------- ( gạch ngang phân số )
1 x 99 + 2.98 + 3.97 + ...... + 99 x 1
tính nhanh (2/3+3/4+5/6+...+99/100).(1/2+2/3+3/4+...+98/99)-(1/2+1/3+...+99/100).(2/3+2/4+...+98/99)
Tính A:B
a)A=98+1/2+1/3+1/4+...+1/99
B=2/3+4/3+5/4+...+100/99
b)A=2018+1/2+1/3+1/4+...+1/2019
B=3/2+4/3+3/4+...+2020/2019
c)A=99/1+98/2+97/3+...+2/98+1/99
B=1/2+1/3+1/4+...+1/100
Giải đầy đủ
1/2*3+1/3*4+1/4*5+1/5*6+1/6*7+...+1/98*99+1/99*100
1+1+2+2+2+3+3+3+4+4+4+5+5+5+6+6+6+7+7+...+99+99+100
( 1/1*2 +1/2*3+1/3*4+1/4*5+.....+1/99*100 ) *10-x=10
tính nhanh
a,(1-1/10)+(1-1/11)+(1-1/12)+...+(1-1/99)+(1-1/100)
b,1/2*3+1/2*4+1/4*5+...+1/99*100
1+1/2*2+1/3*3+1/4*4+.....+1/99*99+1/100*100
\(\frac{101+100+99+98+.....+5+4+3+2+1}{101-100+99-98+...+5-4+3-2+1}\)