Question

1/100 nhé tính giúp mình với

 

\((1+\frac{1}{2})\times(1+\frac{1}{3})\times(1+\frac{1}{4})\times...\times(1+\frac{1}{100})\)

Answer 1

\(\left(1+\frac{1}{2}\right).\left(1+\frac{1}{3}\right).\left(1+\frac{1}{4}\right).......\left(1+\frac{1}{100}\right)\)

= \(\frac{3}{2}.\frac{4}{3}.\frac{5}{4}......\frac{101}{100}\)

= \(\frac{3.4.5....101}{2.3.4.....100}\)

= \(\frac{101}{2}\)

Answer 2

(1+1/2)(1+1/3)(1+1/4)+...+(1+1/100)

=3/2*4/3*5/4*...*101/100

=101/2

=50,5