Question

(-10x^3+2/5y-1/3z).(-1/2xy)

Answer 1

\(\left(-10x^3+\frac{2}{5}y-\frac{1}{3}z\right)\left(-\frac{1}{2}xy\right)=5x^4y-\frac{1}{5}xy^2+\frac{1}{6}xyz\)

Answer 2

\(\left(-10x^3+\frac{2}{5}y-\frac{1}{3}z\right)\left(-\frac{1}{2}xy\right)\)

\(=-10x^3\left(-\frac{1}{2}xy\right)+\frac{2}{5}y\cdot\left(-\frac{1}{2}xy\right)-\frac{1}{3}z\left(-\frac{1}{2}xy\right)\)

\(=\left[\left(-10\right)\cdot\left(-\frac{1}{2}\right)\right]x^4y+\left[\frac{2}{5}\cdot\left(-\frac{1}{2}\right)\right]xy^2-\left[\frac{1}{3}\cdot\left(-\frac{1}{2}\right)\right]xyz\)

\(=5x^4y-\frac{1}{5}xy^2+\frac{1}{6}xyz\)

Answer 3

\(\left(-10x^3+\frac{2}{5}y-\frac{1}{3}z\right).\left(-\frac{1}{2}xy\right)\)

\(=-10x^3.-\frac{1}{2}xy+\frac{2}{5}y.-\frac{1}{2}xy-\frac{1}{3}z.-\frac{1}{2}xy\)

\(=5x^4y-\frac{1}{5}xy^2+\frac{1}{6}xyz\)