\(10+90x=52+8\)
\(100+x=60\)
\(x=60-100\)
\(x=40\)
kmk3cainhaTomori NaoTheo đề ta có:
10 + 90 + x = 52 + 8
100 + x = 60
x = 60 - 100
x = -40
=> 10 + 90 + x =60
=>x=60-10-90
x=50-90
x=-40
k mình nha
\(\Leftrightarrow\)100+x=60
\(\Leftrightarrow\)x=-40
Theo đề ta có:
10 + 90 + x = 52 + 8
100 + x = 60
x = 60 - 100
x = -40
\(10+90+x=52+8\)
\(100+x=60\)
\(x=60-100\)
\(x=-40\)
10+90+x=52+8
(10+90)+x=60
100+x=60
x=60-100
x=-40
10 + 90 + x = 60
100 + x = 60
x = 60 - 100
x = -40
Vậy x = -40