\(10\frac{3}{7}-\left(2\frac{1}{8}+4\frac{3}{7}\right)\)
\(=10\frac{3}{7}-2\frac{1}{8}-4\frac{3}{7}\)
\(=\left(10-4\right)+\left(\frac{3}{7}-\frac{3}{7}\right)-\frac{17}{8}\)
\(=6-\frac{17}{8}\)
\(=\frac{48}{8}-\frac{17}{8}\)
\(=\frac{31}{8}=3\frac{7}{8}\)