A = \(\frac{1}{1.3}+\frac{1}{3.5}+...+\frac{1}{99.101}\)
A = \(\frac{1}{2}\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{99}-\frac{1}{101}\right)\)
A = \(\frac{1}{2}\left(1-\frac{1}{101}\right)=\frac{1}{2}.\frac{100}{101}\)
A = \(\frac{50}{101}\)
B = \(1+\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{1}{630}\)
B = \(1+\frac{2}{6}+\frac{2}{12}+\frac{1}{20}+...+\frac{2}{1260}\)
B = \(1+2\left(\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{35.36}\right)\)
B = \(1+2\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{35}-\frac{1}{36}\right)\)
B = \(1+2\left(\frac{1}{2}-\frac{1}{36}\right)=1+2.\frac{17}{36}\)
B = \(1+\frac{17}{18}\)
B = \(\frac{35}{18}\)
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