Question

1 tính 

A=290-18+567:27

B=1/7 x 31/11 - 1/7 x 9/11 - 1/7

 

Answer 1

Trả lời:

A = 290 - 18 + 567 : 27 

A = 290 - 18 + 21

A = 272 + 21

A = 293

B = 1/7 x 31/11 - 1/7 x 9/11 - 1/7

B = 1/7 x ( 31/11 - 9/11 ) - 1/7

B = 1/7 x 2/1 - 1/7

B = 2/7 - 1/7 

B = 1/7

CHÚC BẠN HỌC TỐT!!!!

Answer 2

a=290-18+567:27

a=290-18+21

a=272+21

a=293

b=1/7×31/11-1/7×9/11-1/7

b=1/7×(31/11-9/11-1)

b=1/7×1

b=1/7

Answer 3

A= 272+ 21= 293

B= \(\frac{1}{7}\)x (\(\frac{31}{11}\)-\(\frac{9}{11}\)) -\(\frac{1}{7}\)

   =  \(\frac{1}{7}\)x  2 - \(\frac{1}{7}\)=  \(\frac{2}{7}\)-  \(\frac{1}{7}\)= \(\frac{1}{7}\)