Bài 1:
\(\left(x^2+x\right)^2+8\left(x^2+x\right)+15=0\)
\(\Leftrightarrow\left(x^2+x\right)^2+3\left(x^2+x\right)+5\left(x^2+x\right)+15=0\)
\(\Leftrightarrow\left(x^2+x+3\right)\left(x^2+x+5\right)=0\)
\(\Leftrightarrow\left[\left(x^2+x+\dfrac{1}{4}\right)+\dfrac{11}{4}\right]\cdot\left[\left(x^2+x+\dfrac{1}{4}\right)+\dfrac{19}{4}\right]=0\)
\(\Leftrightarrow\left[\left(x+\dfrac{1}{2}\right)^2+\dfrac{11}{4}\right]\cdot\left[\left(x+\dfrac{1}{2}\right)^2+\dfrac{19}{4}\right]=0\)(vô lý)
Vậy: \(x\in\varnothing\)