Ta có :
\(5^{2017}:\left(5^{2015}.16+5^{2015}.9\right)\)\(=5^{2017}:\left[5^{2015}\left(16+9\right)\right]\)
\(=5^{2017}:\left[5^{2015}.5^2\right]=1\)
2/ \(4.\left(2017-16x\right)=10^2-2^5\)
\(\Rightarrow4.2017-4.4^2x=100-25\)
\(\Rightarrow8068-4^3.x=75\)
\(\Rightarrow64x=8068-75\)
\(\Rightarrow64x=7993\)
\(\Rightarrow x=\frac{7993}{64}\)