\(\frac{2x-9}{240}=\frac{39}{80}\)
\(\Rightarrow\left(2x-9\right).80=240.39\)
\(160x-720=9360\)
\(160x=9360+720\)
\(160x=10080\)
\(x=10080:160\)
\(x=63\)
Vậy x=63
1. Ta có : \(C=\frac{1010}{1008\cdot8-994}=\frac{1010}{\left(1010-2\right)\cdot8-994}=\frac{1010}{1010\cdot8-16-994}\)
\(=\frac{1010}{1010\cdot8-1010}=\frac{1010}{1010\left(8-1\right)}=\frac{1}{7}\)
\(D=\frac{1\cdot2\cdot3+2\cdot4\cdot6+3\cdot6\cdot9+5\cdot10\cdot15}{1\cdot3\cdot6+2\cdot6\cdot12+3\cdot9\cdot18+5\cdot15\cdot30}\)
\(D=\frac{1\cdot2\cdot3+2\cdot4\cdot6+3\cdot6\cdot9+5\cdot10\cdot15}{1\cdot2\cdot3\cdot3+2\cdot4\cdot6\cdot3+3\cdot6\cdot9\cdot3+5\cdot10\cdot15\cdot3}\)
\(D=\frac{1\cdot2\cdot3+2\cdot4\cdot6+3\cdot6\cdot9+5\cdot10\cdot15}{3\left(1\cdot2\cdot3+2\cdot4\cdot6+3\cdot6\cdot9+5\cdot10\cdot15\right)}=\frac{1}{3}\)
2. \(\frac{2x-9}{240}=\frac{39}{80}\)
=> \(\frac{2x-9}{240}=\frac{39\cdot3}{80\cdot3}=\frac{117}{240}\)
=> 2x - 9 = 117
=> 2x = 117 + 9 = 126
=> x = 126 : 2 = 63