Question

1) 5.(x-2)+27=4x-8

2) 3.(x+1)+2.(x+2)=-13

3)(2x+4).(5-x)=0

4)x² -3x=0

5) x² -3x+2=0

 

Answer 1

1) 5(x - 2) + 27 = 4x - 8

=> 5x - 10 + 27 = 4x - 8

=> 5x + 17 = 4x - 8

=> 5x - 4x = -8 - 17

=> x = -25

2) 3(x + 1) + 2(x  + 2) = -13

=> 3x + 3 + 2x + 4 = -13

=> 5x + 7 = -13

=> 5x = -13 - 7

=> 5x = -20

=> x = -20 : 5

=> x = -4

Answer 2

3) (2x + 4)(5 - x) = 0

=> \(\orbr{\begin{cases}2x+4=0\\5-x=0\end{cases}}\)

=> \(\orbr{\begin{cases}2x=-4\\x=5\end{cases}}\)

=> \(\orbr{\begin{cases}x=-2\\x=5\end{cases}}\)

Vậy ...

4) x² - 3x = 0

=> x(x - 3) = 0

=> \(\orbr{\begin{cases}x=0\\x-3=0\end{cases}}\)

=> \(\orbr{\begin{cases}x=0\\x=3\end{cases}}\)

Vậy ...

5) x² - 3x + 2 = 0

=> x(x - 3) = -2

=> x(x - 3)  = 1 . (1 - 3)

=> x = 1

Answer 3

5)

\(x^2-3x+2=0\)

\(\Leftrightarrow x^2-x-2x+2=0\)

\(\Leftrightarrow x.\left(x-1\right)-2.\left(x-1\right)\)

\(\Leftrightarrow\left(x-2\right).\left(x-1\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x-2=0\\x-1=0\end{cases}\Rightarrow\orbr{\begin{cases}x=2\\x=1\end{cases}}}\)