Tìm x nguyên biết
\(1-3+3^2-3^3+.....+\left(-3\right)^x=\frac{9^{1006}-1}{4}\)
\(1-3+3^2+3^3+...+\left(-3\right)^x=\frac{9^{1006-1}}{4}\)
Tìm x nguyên biết :
\(1-3+3^2-3^3+...+\left(-3\right)^x=\frac{9^{1006}-1}{4}\)
tìm so nguyen x biet: a) \(\frac{1}{1x3}+\frac{1}{3x5}+\frac{1}{5x7}+..........+\frac{1}{\left(2x-1\right)x\left(2x+1\right)}=\frac{49}{99}\)
b) 1-3+32-33+.........+(-3)x=\(\frac{9^{1006}-1}{4}\)
\(1-3+3^2-3^3+.........+\left(-3\right)^x=\frac{9^{1006}-1}{4}\)
Tìm x
ai giải giúp mình bài này mình tích cho
\(1-3+3^2-3^3+......+\left(-3\right)^2=\frac{9^{1006}-1}{4}\)
Tìm x
Cần ghấp ai giải đúng tớ tick cho
\(1-333+3^2-33^3+......+\left(-3\right)^x=\frac{9^{1006}-1}{4}\)
tim x
1.Tìm x biết
a) \(\left(\frac{2}{5}-x\right)\):\(1\frac{1}{3}+\frac{1}{2}=-4\)
b) \(\left(-3+\frac{3}{x}-\frac{1}{3}\right):\left(1+\frac{2}{5}+\frac{2}{3}\right)=-\frac{5}{4}\)
c) \(\frac{-3x}{4}.\left(\frac{1}{x}+\frac{2}{7}\right)=0\)
d) 3-\(\frac{1-\frac{1}{2}}{1+\frac{1}{x}}=2\frac{2}{3}\)
e)\(\left(2x+\frac{1}{3}\right)^2=\frac{9}{16}\)
f) \(4^x+4^{x+3}=4160\)
g) \(\left(x-2,5\right):1\frac{1}{2}=x:2\)
h) \(\left(\frac{1}{3}+x\right):\left(x+\frac{3}{4}\right)=\frac{7}{9}\)
i) 0,81:\(\frac{x}{2}=\frac{16}{x^4}:\left(-0,9\right)\)
2. Tìm x, biết:
a)\(\left(152\frac{2}{4}-148\frac{3}{8}\right):0,2=x:0,3\)
b) \(\left[\left(6\frac{3}{5}-3\frac{3}{14}\right):2,5\right]:\left(21-1,25\right)=x:5\frac{5}{6}\)
Tìm x biết : 1-3+32-33+...+(-3x) = \(\frac{9^{1006}-1}{4}\)