\(12\frac{1}{3}-\left(3\frac{3}{4}+3\frac{4}{4}\right)=\frac{37}{3}-\frac{15}{4}-4=\frac{148-45-48}{12}=\frac{55}{12}\)
tích dùm
có phải là : \(12\frac{1}{3}-\left(3\frac{3}{4}+3\frac{4}{4}\right)\)
\(=\frac{37}{3}-\frac{31}{4}\)
\(=\frac{55}{12}\)
\(12\frac{1}{3}-\left(3\frac{3}{4}+3\frac{4}{4}\right)\)
\(=\frac{37}{3}-\frac{15}{4}-4\)
\(=\frac{148-45-48}{12}\)
\(=\frac{55}{12}\)
\(12\frac{1}{3}\)\(-\left(3\frac{3}{4}+3\frac{4}{4}\right)=\)\(\frac{12\times3+1}{3}-\left(\frac{4\times3+3}{4}+\frac{4\times3+4}{4}\right)=\)\(\frac{34}{3}-\frac{31}{4}=\)\(\frac{34\times4-31\times3}{4\times3}=\frac{136-93}{12}=\frac{43}{12}\)