giải phương trình sau
1/ 2x( x+3) - 6 (x-3) =0
2/ 2x^2( 2x+3) +(2x+3) =0
3/ (x-2) (x+1) -(x-2) 4x =0
4/ 2x ( x-5) -3x +15=0
5/ 3x(x+4) -2x-8 =0
6/ x^2 (2x-6) + 2x -6 =0
Bài 1: tìm x
1, 2x(3x-1)+1-3x=0
2, x\(^2\)(2x-3)+12-8x=0
3, 25(x-1)\(^2\)-4=0
4, 25x\(^2\)-10x+1=0
5, -4x\(^2\)+\(\dfrac{1}{9}\)=0
6, (x-1)\(^3\)=8
7, (2x-1)\(^3\)+27=0
8, 125+\(\dfrac{1}{8}\)(x-1)\(^3\)=0
giải phương trình sau
1/ x^2 -3x+2=0
2/ x^2 -6x+5=0
3/ 2x^2 +5x+3 =0
4/ x^2-8x+15=0
5/ x^2 -x-12=0
Phân tích đa thức thành nhân tử:
1, x^3-x+y^3-4
2, 4x^2-y^2+4x+1
3, x^4+2x^3+x^2
4, x^2+5x-6
5, 7x-6x^2-2
6, 5x^2+5xy-x-y
7, 2x^2+3x-5
8,x^4-5x^2+4
9, x^3-5x^2+45-9x
10, x^4-2x^3-2x^2-2x-3
11, 81x^4+4
12,x^5+x+1
13, x^4+6x^3+7x^2-6x+1
14, x(x+4)(x+6)(x+10)+128
Tìm x
1. x2 - 5x + 6 = 0
2. (x + 4)2 - (3x - 1)2 = 0
3, x2 - 2x + 24 = 0
4, 9x2 - 4 = 0
5, x2 + 2x - 8 = 0
giải phương trình sau
1/ ( x-1) (2x+1) =0
2/ x (2x-1) (3x+15) =0
3/ (2x-6) (3x+4) x=0
4/ (2x-10)(x^2+1)=0
5/ (x^2+3) (2x-1) =0
6/ (3x-1) (2x^2 +1)=0
các bạn giúp mik bài này vs
5) (4x-5).(x+2)-(x+5).(x-3)-3x^2-x
6) (x-3).(x+7)-(2x-1).(x+2)+x.(x-1)
7) (7x-3).(2x+1)-(5x-2).(x+4)-9x^2+17x
8) -2.(x-7).(x+3)+(5x-1).(x+4)-3x^2-27x
9) (6x-5).(x+8)-(3x-1).(2x+3)-9.(4x-3)
10) (8x-1).(x+7)-(x-2).(8x+5)-11.(6x+1).
1) 2x – (3 – 5x) = 4( x +3)
2) 5(2x-3) - 4(5x-7) =19 - 2(x+11)
3) 5x - 4(6-x)(x + 3) = (4-2x)(3-2x) + 2
4) (x - 1)3 - (3x + 2)(-12) = (x2 + 1)(x - 2) - x2
5) (3x -1)2 - (x +3)(2x-1) = 7(x + 1)(x -2) -3x
mn giúp mình vs
Các bạn giúp mình nhé càng nhanh càng tốt nhà
(5x-1). (2x+3)-3. (3x-1)=0
x^3 (2x-3)-x^2 (4x^2-6x+2)=0
x (x-1)-x^2+2x=5
(3x+2)(x-1)-3 (5x+2)+5 (11-4x)=25
8 (x-2)-2 (3x-4)=25
(3x+4). (5x-1)+(5x+2). (1-3x)+2=0
(5x-1). (2x+7)-(2x-3). (5x+9)
4 (x-1). (X+5)-(x+5). (X+2)=3. (X-1)(x+2)
2x^2+3 (x-1). (X+1)=5x(x+1)
4. (18-5x)-12 (3x-7)=1825. (2x-16)-6 .(x+4)
1/2x. (2/5-4x)+(2x+5).x=-13/2
Nhiều các bạn giả đùm mình nha
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