\(-\left(1+2+3+...+2018\right)\)
\(1+2+3+...+2018=\left[\left(2018-1:1+1\right).\left(2018+1\right):2\right]\)
\(=\frac{2018.2019}{2}=1009.2019\)
\(=>-\left(1+2+...+2018\right)=-\left(1009.2019\right)\)
bằng bao nhiêu bn tự tính nha
-1-2-3-...-2018
= - (1+2+...+2018)
= - (1+2018).2018:2
= -2 037 171