Question

1)    1/3x-2/5(x+1)=0

2)     3/4+1/4x=1/2+1/2x

3)      x+2/0,5=2x+1/2

4)      (2x+1)^4=(2x+1)^6

giúp mk vs cảm ơn nhìu

Answer 1

Ta có : (2x + 1)⁴ = (2x + 1)⁶

=> (2x + 1)⁴ - (2x + 1)⁶ = 0

<=> (2x + 1)⁴[1 - (2x + 1)²] = 0

\(\Leftrightarrow\orbr{\begin{cases}\left(2x+1\right)^4=0\\1-\left(2x+1\right)^2=0\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}2x+1=0\\\left(2x+1\right)^2=1\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}2x=-1\\\left(2x+1\right)=1;-1\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=-\frac{1}{2}\\2x=0;-2\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=-\frac{1}{2}\\x=0;-1\end{cases}}\)

Vậy x thuộc \(-\frac{1}{2};0;-1\)

Answer 2

hk hỉu j hết bn ạ

Answer 3

còn mấy câu hs kia giúp thì giúp cho trot lun nha