=\(\frac{1}{2}\)x\(\frac{2}{3}\)x........x \(\frac{2010}{2011}\)
=\(\frac{1x2x......x2010}{2x3x....x2011}\)
=\(\frac{1}{2011}\)
=\(\frac{1}{2}\)x\(\frac{2}{3}\)x........x \(\frac{2010}{2011}\)
=\(\frac{1x2x......x2010}{2x3x....x2011}\)
=\(\frac{1}{2011}\)
Cho K = 1 + ( 1 + 2 ) + ( 1 + 2 + 3 ) + .... + ( 1 + 2 + 3 + .... + 2012 ) / 2012 x 1 + 2011 x 2 + 2010 x 3 + .. + 2 x 2011 + 1 x 2012 .
Tính K .
tìm x:
a,( 3/2 - 0,5 ) : x = 7/2 + 1/4
b,( X x 0,25 + 2010 ) x 2011 = ( 53 + 2010 ) x ( 2012 - 1 )
Cho K:\(\frac{1+\left(1+2\right)+\left(1+2+3\right)+........+\left(1+2+3+........+2012\right)}{2012\text{x}1+2011\text{x}2+2010\text{x}3+.............+1\text{x}2012}\)
Tính K cộng với 2011
Tính:
( 1 - 1/35) x (1 - 1/36) x...x (1 - 1/2010) x (1 - 1/2011)
MN giúp mình nha
1 + ( 1 + 2 ) + ( 1 + 2 + 3 ) + ... + ( 1 + 2 + 3 + ... + 2012 )
2012 x 1 + 2011 x 2 + 2010 x 3 + ... + 2 x 2011 + 1 x 2012
Giúp tớ giải nốt 2 bài tính nhanh này nhé, thanks
B = 1/3 + 1/6 + 1/10 + 1/15 + 1/21 + 1/28
D = 2009 x 2010 + 2000 / 2011 x 2010 - 2020
tìm x : X x [1-1/3] x [1-1/4] x [1-1/5] x .......x [1-1/2011] = 2/2012
tìm x : x x [1-1/3] x [1-1/4] x [1-1/5] x .......x [1-1/2011] = 2/2012
1/(2 x 2)+ 1/(3 x 3)+ 1/(4 x 4)+… + 1/(2011 x 2011)
So sánh A với 3/4