Câu 1:
\(n_{Na_2CO_3}=\dfrac{10,6}{106}=0,1\left(mol\right)\)
\(Na_2CO_3+2HCl\rightarrow2NaCl+H_2O+CO_2\)
0,1--------->0,2----->0,2---------------->0,1
a. \(V_{CO_2}=0,1.22,4=2,24\left(l\right)\)
b. \(m_{dd.HCl}=\dfrac{0,2.36,5.100\%}{3,65}=200\left(g\right)\)
c. \(C\%_{NaCl}=\dfrac{58,5.0,2.100\%}{10,6+200-0,1.44}=5,67\%\)
Câu 2:
\(n_{NaCl}=0,5.2=1\left(mol\right)\\ n_{AgNO_3}=0,6.2=1,2\left(mol\right)\)
\(NaCl+AgNO_3\rightarrow NaNO_3+AgCl\)
1------->1---------->1----------->1
Xét: \(\dfrac{1,2}{1}>1\Rightarrow AgNO_3.dư\)
\(m_{kt}=m_{AgCl}=1.143,5=143,5\left(g\right)\)
b.
\(n_{AgNO_3.dư}=1,2-1=0,2\left(mol\right)\)
\(CM_{AgNO_3.dư}=\dfrac{0,2}{0,5+0,6}=\dfrac{2}{11}M\)
\(CM_{NaNO_3}=\dfrac{1}{0,5+0,6}=\dfrac{10}{11}M\)
