\(Cu+2AgNO_3->Cu\left(NO_3\right)_2+2Ag\\ a.n_{Cu\left(pư\right)}=a\\ 2,16-0,64=a\left(108.2-64\right)\\ a=0,01mol\\ b.n_{AgNO_3}=0,2mol\\ C_{M\left(AgNO_3\left(dư\right)\right)}=\dfrac{0,18}{0,2}=0,9M\\ C_{M\left(Cu\left(NO_3\right)_2\right)}=\dfrac{0,01}{0,2}=0,05M\)