a) PTHH: \(Zn+2HCl\rightarrow ZnCl_2+H_2\uparrow\)
Ta có: \(n_{Zn}=\dfrac{19,5}{65}=0,3\left(mol\right)=n_{ZnCl_2}=n_{H_2}\)
\(\Rightarrow m_{ZnCl_2}=0,3\cdot136=40,8\left(g\right)\)
b) PTHH: \(Fe_2O_3+3H_2\xrightarrow[]{t^o}2Fe+3H_2O\)
Ta có: \(\left\{{}\begin{matrix}n_{H_2}=0,3\left(mol\right)\\n_{Fe_2O_3}=\dfrac{32}{160}=0,2\left(mol\right)\end{matrix}\right.\)
Xét tỉ lệ: \(\dfrac{0,2}{1}>\dfrac{0,3}{3}\) \(\Rightarrow\) Oxit còn dư, Hidro p/ứ hết
\(\Rightarrow n_{Fe}=0,2\left(mol\right)\) \(\Rightarrow m_{Fe}=0,2\cdot56=11,2\left(g\right)\)
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