b.
\(n_{NaOH}\)=\(\dfrac{20}{40}\)=0,5 (mol)
\(n_{N_2}\)=\(\dfrac{11,2}{22,4}\)=0,5 (mol)
\(n_{NH3}\)=\(\dfrac{7,2.10^{23}}{6.10^{23}}\)=1,2 (mol)
c.
\(m_{Al_2O_3}\)=0,15.102=15,3 (g)
\(n_{SO_2}\)=\(\dfrac{6,72}{22,4}\)=0,3 (mol)
\(m_{SO_2}\)=0,3.64=19,2 (g)
\(n_{H_2S}\)=\(\dfrac{0,6.10^{23}}{6.10^{23}}\)=0,1 (mol)
\(m_{H_2S}\)=0,1.22,4=4,4 (g)
d.
\(v_{CO_2}\)=0,2.22,4=4,48 lít
\(n_{SO_2}\)=\(\dfrac{16}{64}\)=0,25 (mol)
\(\Rightarrow v_{so_2}\)=0,25.22,4=5,6 lít
\(n_{CH_4}\)=\(\dfrac{2,1.10^{23}}{6.10^{23}}\)=0,35 (mol)
\(\Rightarrow V_{CH_4}\)=0,35.22,4=7,84 lít
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