Question

Answer 1

\(=\left(x+y\right)^2\left(x-y\right)+y^2\left(x-y\right)\)

\(=\left(x-y\right)\cdot\left[x^2+2xy+y^2+y^2\right]\)

\(=\left(x-y\right)\left(x^2+2xy+2y^2\right)\)

Answer 2

= x.(x+y)²-y.(x+y)²+y².(x-y)

= (x+y)².(x-y)+y².(x-y)

= (x-y).[(x+y)²+y²)

=(x-y).(x²+2xy+y²+y²)

=(x-y).(x²+2xy+2y²)

Answer 3

 x.(x+y)²-y.(x+y)²+y².(x-y)

= (x+y)².(x-y)+y².(x-y)

= (x-y).[(x+y)²+y²)

=(x-y).(x²+2xy+y²+y²)

=(x-y).(x²+2xy+2y²)