\(a.2KClO_3-^{t^o,MnO_2}\rightarrow2KCl+3O_2\uparrow\\ 2Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2\uparrow\\ b.KhíX:O_2\\ KhíY:H_2\\ TN1:n_{KClO_3}=\dfrac{24,5}{122,5}=0,2\left(mol\right)\\ n_{O_2}=\dfrac{3}{2}n_{KClO_3}=0,3\left(mol\right)\\ \Rightarrow V_{O_2}=0,3.22,4=6,72\left(l\right)\\ TN2:n_{Al}=\dfrac{2,7}{27}=0,1\left(mol\right)\\ n_{H_2}=\dfrac{3}{2}n_{Al}=0,15\left(mol\right)\\ \Rightarrow V_{H_2}=0,15.22,4=3,36\left(l\right)\\ c.2H_2+O_2-^{t^o}\rightarrow2H_2O\\ LTL:\dfrac{0,3}{2}=\dfrac{0,15}{1}\Rightarrow2chấtđềuphảnứnghết\\ n_{H_2O}=n_{H_2}=0,3\left(mol\right)\\ \Rightarrow m_{H_2O}=0,3.18=5,4\left(g\right)\)
