PTHH: \(2Al+6HCl\rightarrow2AlCl_3+3H_2\uparrow\)
Ta có: \(n_{Al}=\dfrac{0,54}{27}=0,02\left(mol\right)\)
\(\Rightarrow\left\{{}\begin{matrix}n_{AlCl_3}=0,02\left(mol\right)\\n_{H_2}=0,03\left(mol\right)\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}m_{AlCl_3}=0,02\cdot133,5=2,67\left(g\right)\\V_{H_2}=0,03\cdot22,4=0,672\left(l\right)\end{matrix}\right.\)