Question

Answer 1

a: =>5(2x-1)-3(x-2)=x+7

=>10x-5-3x+6=x+7

=>7x+1=x+7

=>6x=6

hay x=1

b: =>(x-5)(2x+3)=0

=>x=5 hoặc x=-3/2

Answer 2

\(a)PT\Leftrightarrow\dfrac{10x-5-3x+6}{15}=\dfrac{x+7}{15}.\\ \Rightarrow7x+1=x+7.\\ \Leftrightarrow6x=6.\\ \Leftrightarrow x=1.\\ b)PT\Leftrightarrow\left(2x+3\right)\left(x-5\right)=0.\)

\(\Leftrightarrow\left[{}\begin{matrix}2x+3=0.\\x-5=0.\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{-3}{2}.\\x=5.\end{matrix}\right.\)