\(\left(5x+1\right)^2=\dfrac{36}{49}\)
\(\Leftrightarrow\left(5x+1\right)^2=\left(\pm\dfrac{6}{7}\right)^2\)
\(\Leftrightarrow\)\(\left[{}\begin{matrix}5x+1=\dfrac{6}{7}\\5x+1=-\dfrac{6}{7}\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{35}\\x=-\dfrac{13}{35}\end{matrix}\right.\)
\(\Rightarrow D\)
⇔(5x+1)2=(±67)2⇔(5x+1)2=(±67)2
⇔⇔⇔⎡⎢ ⎢⎣x=−135x=−1335

