Lời giải:
$(-n)^3.3^8=-27=-3^3$
$(-n)^3=-3^{-5}$
$n^3=3^{-5}$
$n=\sqrt[3]{\frac{1}{243}}$
Chương I : Số hữu tỉ. Số thực
Các câu hỏi tương tự
(-3/8+5/32):-4/5-(-3/5) mũ 3 + -5/8+27/32.5/4
(3x + 21)3= \(\dfrac{27}{8}\)
Bài 1:Tính1) (1/2)^3 (3/2)^2 2) (2/3)^3 (3/2)^5 3) (5/4)^5 (4/5)^7 4) (-5/6)^6 (6/5)^8 5)(-4/3)^3 (9/16)^5 6) (1/3)^4 (-9/2)^6 7)(-4/9)^3 (-27/20)^4 8) (0,2)^4 . 5^6 9) (-4/3)^3 (9/16)^5 10) (-0,2)^3 .(-5)^5 11) (-4)^4 .(0,25)^6 12) $^2 . (0,2)^3 13) (0,5)^2 . 2^4 14) (-0,5)^3 .2^6 15) (-0,5)^5 .(-2)^10 16) (0,125)^2 .8^4 17) (0,125)^5 . (-8)^4...
Đọc tiếp
Bài 1:Tính
1) (1/2)^3 (3/2)^2
2) (2/3)^3 (3/2)^5
3) (5/4)^5 (4/5)^7
4) (-5/6)^6 (6/5)^8
5)(-4/3)^3 (9/16)^5
6) (1/3)^4 (-9/2)^6
7)(-4/9)^3 (-27/20)^4
8) (0,2)^4 . 5^6
9) (-4/3)^3 (9/16)^5
10) (-0,2)^3 .(-5)^5
11) (-4)^4 .(0,25)^6
12) $^2 . (0,2)^3
13) (0,5)^2 . 2^4
14) (-0,5)^3 .2^6
15) (-0,5)^5 .(-2)^10
16) (0,125)^2 .8^4
17) (0,125)^5 . (-8)^4
18) (-0,125)^7 . 8^10
19) (-0,1)^4 . 10^7
20) (0,1)^5 . (-10)^10
Giúp mình với ạ,mình cảm ơn ạ
Tìm x :
1/ \(\frac{x^7}{81}=27\)
2/ \(\left(x^4\right)^2=\frac{x^{12}}{x^5}\)
3/ \(x^{10}=25.x^8\)
4/ \(\left(3x-1\right)^3=\frac{-8}{27}\)
nếu làm nhanh ngay thì tick và followwwww
B = -3 - 2/3 + 3/5 (-10/9 - 25/3) - 5/6
C = (12/35 - 6/7 + 18/14 : 6/-7 - -2/5-1
D = [(-54/64 - (1/9 : 8/27 :-81/128]
-5/8 - 7/1
-8/28-15/27
-1/39+ -1/52
-6/9 + -12/16
-2/5 - -3/11
93.275/813.313. / là dấu gạch phân số
Chứng minh rằng:
\(\dfrac{\left(2^8-2^6\right)^3}{64^4}=\dfrac{27}{64}\)
Tìm x, biết:
a) \(\left(\frac{-3}{4}\right)^{3x-1}=\frac{-27}{64}\)
b) \(\left(\frac{4}{5}\right)^{2x+5}=\frac{256}{265}\)
c) \(\frac{\left(x+3\right)^5}{\left(x+3\right)^2}=\frac{64}{27}\)
d) \(\left(x-\frac{2}{15}\right)^3=\frac{8}{125}\)