PTHH: \(CuO+2HCl\rightarrow CuCl_2+H_2O\)
a______2a
\(Fe_2O_3+6HCl\rightarrow2FeCl_3+3H_2O\)
b______6b
Ta lập HPT: \(\left\{{}\begin{matrix}80a+160b=20\\2a+6b=0,4\cdot1,75\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}a=0,05\\b=0,1\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}\%m_{CuO}=\dfrac{0,05\cdot80}{20}\cdot100\%=20\%\\\%m_{Fe_2O_3}=80\%\end{matrix}\right.\)