\(1,=11+6\sqrt{2}-\dfrac{6\left(\sqrt{2}+1\right)}{2-1}+3\sqrt{2}\\ =11+6\sqrt{2}-6\sqrt{2}-6+3\sqrt{2}=5+3\sqrt{2}\\ 2,=32-6\sqrt{28}+6\sqrt{28}=32\\ 3,=\dfrac{\left(4-2\sqrt{3}\right)\left(2+\sqrt{3}\right)}{4-3}+\sqrt{3}-\sqrt{3}\\ =8+4\sqrt{3}-4\sqrt{3}-6=2\\ 4,=\dfrac{5\left(\sqrt{3}-\sqrt{2}\right)\left(5-2\sqrt{6}\right)}{5\left(\sqrt{3}-\sqrt{2}\right)}=5-2\sqrt{6}\)
\(5,=\left(12\sqrt{3}-8\sqrt{3}-25\sqrt{3}\right):2\sqrt{3}\\ =-21\sqrt{3}:2\sqrt{3}=-\dfrac{21}{2}\\ 6,=\left(2\sqrt{2}\right)^2-\left(\sqrt{3}-3\right)^2\\ =8-9+6\sqrt{3}=6\sqrt{3}-1\\ 7,=3\sqrt{a}+4\sqrt{a}-3\sqrt{a}=4\sqrt{a}\left(a>0\right)\\ 8,=3\sqrt{ab}+\dfrac{2b\sqrt{a}}{\sqrt{b}}-\dfrac{3b\sqrt{b}}{\sqrt{a}}\\ =3\sqrt{ab}+2\sqrt{ab}-\dfrac{3b\sqrt{ab}}{a}\\ =\dfrac{5a\sqrt{ab}-3b\sqrt{ab}}{a}\)
7: \(3\sqrt{a}+8\sqrt{\dfrac{a}{4}}-a\sqrt{\dfrac{9}{a}}\)
\(=3\sqrt{a}+4\sqrt{a}-3\sqrt{a}\)
\(=4\sqrt{a}\)
