Question

Answer 1

Lời giải:

a. $\sqrt{x}=1\Leftrightarrow (\sqrt{x})^2=1$

$\Leftrightarrow x=1$

b.

$\sqrt{9x}=6\Leftrightarrow 9x=6^2=36$

$\Leftrightarrow x=4$

c.

$3\sqrt{x}-1=0$

$\Leftrightarrow \sqrt{x}=\frac{1}{3}$

$\Leftrightarrow x=(\frac{1}{3})^2=\frac{1}{9}$

d.

$\sqrt{16(x-3)}=8$

$\Leftrightarro 16(x-3)=8^2=64$

$\Leftrightarrow x-3=4$

$\Leftrightarrow x=7$

Answer 2

a: Ta có: \(\sqrt{x}=1\)

nên x=1

b: Ta có: \(\sqrt{9x}=6\)

\(\Leftrightarrow9x=36\)

hay x=4

c: Ta có: \(3\sqrt{x}-1=0\)

\(\Leftrightarrow3\sqrt{x}=1\)

\(\Leftrightarrow\sqrt{x}=\dfrac{1}{3}\)

hay \(x=\dfrac{1}{9}\)

Answer 3

d: Ta có: \(\sqrt{16\left(x-3\right)}=8\)

\(\Leftrightarrow16\left(x-3\right)=64\)

\(\Leftrightarrow x-3=4\)

hay x=7