Bài 6:
a: 0,(26)=0,2626...
mà 0,2626...>0,261
nên 0,(26)>0,261
b: 0,15>0,14
=>0,15>0,14(9)
BÀi 4:
a: \(0,\left(3\right)+3\frac13+0,4\left(2\right)\)
\(=\frac13+3+\frac13+\frac{42-4}{90}=\frac23+3+\frac{38}{90}\)
\(=\frac{60}{90}+\frac{270}{90}+\frac{38}{90}=\frac{368}{90}=\frac{184}{45}\)
b: \(\frac49+1,2\left(31\right)-0,\left(13\right)\)
\(=\frac49+\frac{1219}{990}-\frac{13}{99}\)
\(=\frac{440}{990}+\frac{1219}{990}-\frac{130}{990}=\frac{1529}{990}\)
c: \(2,\left(4\right)\cdot\frac{3}{11}=\frac{22}{9}\cdot\frac{3}{11}=\frac13\cdot2=\frac23\)
d: \(-0,\left(3\right)+\frac13=-\frac13+\frac13=0\)
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