Question

Answer 1

a: Ta có: \(\sqrt{6-4\sqrt{2}}-\sqrt{6+4\sqrt{2}}\)

\(=2-\sqrt{2}-2-\sqrt{2}\)

\(=-2\sqrt{2}\)

b: Ta có: \(\sqrt{14+6\sqrt{5}}-\sqrt{14-6\sqrt{5}}\)

\(=3+\sqrt{5}-3+\sqrt{5}\)

\(=2\sqrt{5}\)

Answer 2

a) \(\sqrt{6-4\sqrt{2}}-\sqrt{6+4\sqrt{2}}=2-\sqrt{2}-2-\sqrt{2}=-2\sqrt{2}\)

b) \(\sqrt{14+6\sqrt{5}}-\sqrt{14-6\sqrt{5}}=3+\sqrt{5}-3+\sqrt{5}=2\sqrt{5}\)

c) \(\sqrt{11+4\sqrt{7}}-\sqrt{11-4\sqrt{7}}=\sqrt{7}+2-\sqrt{7}+2=4\)

d) \(\sqrt{19-8\sqrt{3}}+\sqrt{19+8\sqrt{3}}=4-\sqrt{3}+4+\sqrt{3}=8\)