Question

Phân tích đa thức sau:

\(49\left(y-4\right)^2-9\left(y+2\right)^2\)

Answer 1

$49{\left(y-4\right)}^2-9{\left(y+2\right)}^2$

= [ 7 ( y - 4 ) ]\(^2\) - [ 3 ( y + 2 ) ]\(^2\)

= [ 7 (y - 4 ) - 3 ( y + 2 ) ] [ 7( y - 4 ) + 3 ( y + 2 ) ]

= ( 7y - 28 - 3y - 6 ) ( 7y - 28 + 3y + 6 )

= ( 4y - 34 )( 10y - 22 )

Answer 2

$49{\left(y-4\right)}^2-9{\left(y+2\right)}^2$

= [ 7 ( y - 4 ) ]\(^2\) - [ 3 ( y + 2 ) ]\(^2\)

= [ 7 ( y - 4 ) - 3 (y + 2 ) ] [ 7 (y - 4 )+ 3 ( y + 2 ) ]

= ( 7y - 28 - 3y - 6 ) ( 7y - 28 + 3y + 6 )

= ( 4y - 34 ) ( 10y - 22 )

Answer 3

$49{\left(y-4\right)}^2-9{\left(y+2\right)}^2$

= [ 7 ( y - 4 ) ]\(^2\) - [ 3 ( y + 2 ) ]\(^2\)

= [ 7 ( y - 4 ) - 3 ( y + 2 ) ] [ 7 ( y - 4 ) + 3 ( y + 2 )]

= ( 7y - 28 - 3y - 6 ) ( 7y -28 + 3y + 6 )

= ( 4y - 34 ) ( 10y - 22 )

Answer 4

$49{\left(y-4\right)}^2-9{\left(y+2\right)}^2$

= [ 7 ( y - 4 ) ]\(^2\) - [ 3 ( y + 2 ) ]\(^2\)

= [ 7 ( y - 4 ) - 3 ( y + 2 ) ] [ 7 ( y - 4 ) + 3 ( y + 2 ) ]

= ( 7y - 28 - 3y - 6 ) ( 7y - 28 + 3y + 6 )

= ( 4y - 34 ) ( 10y - 22 )

Answer 5

Answer 6

Phân tích đa thức sau:

\(49\left(y-4\right)^2-9\left(y+2\right)^2\) \(=\left[7\left(y-4\right)\right]^2-\left[3\left(y+2\right)^2\right]\)

\(=\left(7y-28\right)^2-\left(3y+6\right)^2\) \(=\left(7y-28-3y-6\right)\left(7y-28+3y+6\right)\)

\(=\left(4y-34\right)\left(10y-22\right)\)