Question

2,4g Mg + H2SO4 30%

a) VH2

b)mdd H2SO4

C)mdd sau phản ứng

d) C% ddA

Answer 1

Mg + H₂SO₄ → MgSO₄ + H₂

\(n_{Mg}=\frac{2,4}{24}=0,1\left(mol\right)\)

a) Theo PT: \(n_{H_2}=n_{Mg}=0,1\left(mol\right)\)

\(\Rightarrow V_{H_2}=0,1\times22,4=2,24\left(l\right)\)

b) Theo pT: \(n_{H_2SO_4}=0,1\times98=9,8\left(g\right)\)

\(\Rightarrow m_{ddH_2SO_4}=\frac{9,8}{30\%}=32,67\left(g\right)\)

c) \(m_{H_2}=0,1\times2=0,2\left(g\right)\)

Ta có: \(m_{dd}saupư=2,4+32,67-0,2=34,87\left(g\right)\)

d) Theo pT: \(n_{MgSO_4}=n_{Mg}=0,1\left(mol\right)\)

\(\Rightarrow m_{MgSO_4}=0,1\times120=12\left(g\right)\)

\(\Rightarrow C\%_{MgSO_4}=\frac{12}{34,87}\times100\%=34,41\%\)