\(\sqrt[3]{10+6\sqrt{3}}.\left(\sqrt{3}-1\right)\)
\(=\sqrt[3]{1+3\sqrt{3}+9+3\sqrt{3}}\left(\sqrt{3}-1\right)\)
\(=\sqrt[3]{\left(1+\sqrt{3}\right)^3}\left(\sqrt{3}-1\right)\)
\(=\left(1+\sqrt{3}\right)\left(\sqrt{3}-1\right)\)
\(=\sqrt{3}^2-1^2=3-1=2\)
A =\(\dfrac{x\sqrt[]{x}-3}{x-2\sqrt[]{x}-3}-\dfrac{2\left(\sqrt[]{x}-3\right)}{\sqrt[]{x}+1}+\dfrac{\sqrt[]{x}+3}{3-\sqrt[]{x}}\)
a. rút gọn A
b. Tính A với x = \(14-6\sqrt[]{5}\)
c. tìm min A
A=\(\dfrac{x\sqrt{x}-3}{x-2\sqrt{x}-3}-\dfrac{2\left(\sqrt{x}-3\right)}{\sqrt{x}+1}+\dfrac{\sqrt{x}+3}{3-\sqrt{x}}\)
a) Rút gọn A
b) Tính A với x=14-6\(\sqrt{5}\)
c) Tìm Min A
Thực hiện các phép tính sau:
a)\(\sqrt[3]{\left(4-2\sqrt[3]{3}\right)\left(\sqrt[3]{3}-1\right)}\)
b)\(\sqrt{3+\sqrt{3}+\sqrt[3]{10+6\sqrt{3}}}\)
so sánh
\(;\sqrt{2}+1vs\sqrt[3]{7+5\sqrt{2};}\) \(-6\sqrt[3]{7}\&7\sqrt[3]{\left(-6\right)}\)\(;\sqrt[3]{4}+\sqrt[3]{7}\&\sqrt[3]{11}\)\(;\sqrt[3]{10}-2vs\sqrt[3]{2}\)
Rút gọn
\(\sqrt[3]{4-2\sqrt{6}}+\sqrt[3]{4+2\sqrt{6}}\)
Tính:
a) \(\sqrt[3]{\left(\sqrt{2}+1\right)\left(3+2\sqrt{2}\right)}\)
b) \(\sqrt[3]{\left(4-2\sqrt{3}\right)\left(\sqrt{3}-1\right)}\)
c) \(\left(\sqrt[3]{4}+1\right)^3-\left(\sqrt[3]{4}-1\right)^3\)
d) \(\left(\sqrt[3]{9}-\sqrt[3]{6}+\sqrt[3]{4}\right)\left(\sqrt[3]{3}+\sqrt[3]{2}\right)\)
e) \(\sqrt[3]{20+14\sqrt{2}}+\sqrt[3]{20-14\sqrt{2}}\)
Mọi người giúp em với ạ!!!!!!!!!!!
Rút gọn BT với \(x>0;x\ne8\)
\(P=\dfrac{8-x}{2+\sqrt[3]{x}}:\left(2+\dfrac{\sqrt[3]{x^2}}{2+\sqrt[3]{x}}\right)+\left(\sqrt[3]{x}+\dfrac{2\sqrt[3]{x}}{\sqrt[3]{x}-2}\right)\left(\dfrac{\sqrt[3]{x^2}-1}{\sqrt[3]{x^2}+2\sqrt[3]{x}}\right)\)
10.cho biểu thức:p=\(\left(\dfrac{1-a\sqrt{a}}{1-\sqrt{a}}+\sqrt{a}\right).\left(\dfrac{1+a\sqrt{a}}{1+\sqrt{a}}-\sqrt{a}\right)\)
a) rút gọn p
b)tìm a để p \(< 7-4\sqrt{3}\)
thực hiện phép tính
a)\(\left(\frac{1}{2}\sqrt[3]{9}-2\sqrt[3]{3}+3\sqrt[3]{\frac{1}{3}}\right):2\sqrt[3]{\frac{1}{3}}\)
b)\(\left(\sqrt[3]{9}-\sqrt[3]{6}+\sqrt[3]{4}\right)\left(\sqrt[3]{3}+\sqrt[3]{2}\right)\)
