\(\sqrt{2x^2+x-1}-x\sqrt{x+1}-2x-1=x\sqrt{2x-1}\)
Điều kiện: \(x\ge\dfrac{1}{2}\)
\(\Leftrightarrow-2\sqrt{2x^2+x-1}+2x\sqrt{x+1}+4x+2+2x\sqrt{2x-1}=0\)
\(\Leftrightarrow\left(\sqrt{2x-1}-\sqrt{x+1}\right)^2+2x\sqrt{x+1}+x+2+2x\sqrt{2x-1}=0\)
Ta có \(VT>0\) nên vô nghiệm