Giải:
ĐKXĐ: \(a\ge0\)
\(\dfrac{a-\sqrt{3a}+3}{a\sqrt{a}+3\sqrt{3}}\)
\(=\dfrac{a-\sqrt{3a}+3}{\left(\sqrt{a}\right)^3+\left(\sqrt{3}\right)^3}\)
\(=\dfrac{a-\sqrt{3a}+3}{\left(\sqrt{a}+\sqrt{3}\right)\left(a-\sqrt{3a}+3\right)}\)
\(=\dfrac{1}{\sqrt{a}+\sqrt{3}}\)
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