\(SO_2+2NaOH\rightarrow Na_2SO_3+H_2O\)
0,13 0,13 0,13 0,13
\(n_{SO_2}=\dfrac{V}{22,4}=\dfrac{3,36}{22,4}=0,15mol\)
\(n_{Na_2SO_3}=\dfrac{m}{M}=\dfrac{16,7}{126}=0,13mol\)
\(C_{M_{NaOH}}=\dfrac{n}{V}\)\(=\dfrac{0,15}{0,4}\)\(=0,325M\)
vậy C=0,325M