\(x\left(x-2\right)-x+2=0\)
\(\Leftrightarrow x^2-3x+2=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\x-1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=1\end{matrix}\right.\)
Vậy \(S=\left\{2;1\right\}\).
1. Tìm x:
a) x2 - 3x = 0
b) 2x ( x - 2 ) - (x - 2 ) = 0
c) x + 5x2 = 0
d) x + 1 = ( x + 1 )2
e) x3 + x = 0
f) 5 ( x + 3 ) - 2x ( 3 + x ) = 0
h) 6x ( x2 - 2 ) - ( 2 - x2 ) = 0
i) ( x + 1 )2 - ( x + 1 ) ( x - 2 ) = 0
Giúp mk nha
Tìm x ( Đưa các biểu thức đã cho về dạng A(x).B(x)=0 )
a.x^3-x=0
b.x^3+x=0
c.x^2-4x=0
d.x(x-1)-2(1-x)=0
e.2x(x-2)-(2-x)^2=0
f.4x(x+1)=8(x+1)
g.5x(x-20)-x+2=0
h.(x+1)=(x+1)^2
Tìm x biết a) x(x-25)=0 b)2x(x-4)-x(2x-1)=-28 c)x^2 -5x=0 d)(x-2)^2-(x+1)(x+3)=-7 e)(3x+5).(4-3x)=0 f)x^2-1/4=0
Bài 2 :Tìm x, biết
a, 2-x = 2 ( x-2)^3
b, ( x-1,5)^6 + 2 ( 1,5-x)^2 = 0
c, 2x^3 + 3x^2 + 3 + 2x = 0
d, x^2 (x+1) - x(x+1) + x(x-1) = 0
f, x^3 - 4x - 14x (x-2) = 0
Giúp mk vs ạ mk đang cần gấp
a) (x-3)3-3+x=0
b)5x(x-2)-(2+x)=0
c)5x(x-2000)-x+2000=0
d)x2-4x=0
giúp mình với mình cần gấp
tìm x, biết:
x2-25-(x+5)=0
(2x-1)2-4x2-1=0
x2(x2+4)-x2-4=0
Tìm x, biết:
a) x - 1 + 2 x ( x - 1 ) = 0
b) x3 ( x2 - 1 ) - x ( 2 - x2) = 0
2,Tìm x,biết:
a,x2(x+1)+2x(x+1)=0 b,x(3x-2)-5(2-3x)=0
c,\(\dfrac{4}{9}\) -25x2=0 d,x2-x+\(\dfrac{1}{4}\) =0
x + 5x^2 = 0
x+1 = (x+1)^2
x^3 + x = 0
tìm x biết
a) 7x(x-2)=(x-2)
b) 4x^2-9-x(2x-3)=0
c) x^3+5x^2+9x=-45
d) x^3-6x^2-x+30=0
e) x^2+16=10x
