Yêu cầu làm gì bạn?
Mà dù đề yêu cầu thế nào thì chắc chắn bài này sẽ phải qua bước biến đổi sau:
\(x-1=\sqrt[3]{4+\sqrt{8}}+\sqrt[3]{4-\sqrt{8}}\)
\(\Leftrightarrow x^3-3x^2+3x-1=8+3\sqrt[3]{16-8}.x\)
\(\Leftrightarrow x^3-3x^2+3x-1=8+6x\)
\(\Leftrightarrow x^3-3x^2-3x-9=0\)
Tính:
\(E=\frac{\sqrt{\sqrt{2}-1}.\sqrt[4]{3+2\sqrt{2}}+\sqrt[3]{\sqrt{x}\left(x+12\right)-6x-8}}{\frac{x-\sqrt{x}}{\sqrt{x}-1}-\sqrt{\sqrt{2}+1}.\sqrt[4]{3-2\sqrt{2}}}\)
\(1,x=\sqrt{3-x}.\sqrt{4-x}+\sqrt{4-x}.\sqrt{5-x}+\sqrt{5-x}.\sqrt{3-x}\)
2) \(\dfrac{x^2-4}{x}+\dfrac{y^2-4}{y}+8=4\left(\sqrt{x-1}+\sqrt{y-1}\right)\)
giải pt :
a) \(\sqrt{x-1}+\sqrt{x^3+x^2+x+1}=1+\sqrt{x^4-1}\)
b0 \(4\sqrt{x+1}=x^2-5x+14\)
c) \(2x+3\sqrt{4-5x}+\sqrt{x+2}=8\)
d) \(\dfrac{x^2+x}{\sqrt{x^2+x+1}}=\dfrac{2-x}{\sqrt{x-1}}\)
giải phương trình \(\sqrt{x-4\sqrt{x-1}+3}+\sqrt{x-6\sqrt{x-1}+8}=1\)
Giải các phương trình sau:
a, \(\sqrt{x^2-6x+9}+\sqrt{2x^2+8x+8}=\sqrt{x^2-2x+1}\)
b, \(\sqrt{x-3-2\sqrt{x-4}}+\sqrt{x-4\sqrt{x-1}}=1\)
c. \(\sqrt{x+8-6\sqrt{x-1}}=4\)
d, \(\sqrt{x\left(x-3\right)}+\sqrt{x\left(x-4\right)}=2\sqrt{x^2}\)
e, \(\sqrt{\left(x+3\right)\left(x+2\right)}+\sqrt{\left(x+3\right)\left(x-1\right)}=2\sqrt{\left(x+3\right)^2}\)
Tính
\(c,\frac{x\sqrt{x}-2x+28}{x-3\sqrt{x}-4}-\frac{\sqrt{x}-4}{\sqrt{x}+1}+\frac{\sqrt{x}+8}{4-\sqrt{x}}\left(x>0,x\ne16\right)\)
\(d,\sqrt{6+2\sqrt{2}.\sqrt{3-\sqrt{4+2\sqrt{3}}}}\)
Giúp nha plsss
Giải các pt sau:
a) \(\sqrt{x+8}+\frac{9x}{\sqrt{x+8}}-6\sqrt{x}=0\)
b) \(x^4-2x^3+\sqrt{2x^3+x^2+2}-2=0\)
c) \(3x\sqrt[3]{x+7}\left(x+\sqrt[3]{x+7}\right)=7x^3+12x^2+5x-6\)
d) \(4x^2+\left(8x-4\right)\sqrt{x}-1=3x+2\sqrt{2x^2+5x-3}\)
e) \(16x^2+19x+7+4\sqrt{-3x^2+5x+2}=\left(8x+2\right)\left(\sqrt{2-x}+2\sqrt{3x+1}\right)\)
f) \(\left(5x+8\right)\sqrt{2x-1}+7x\sqrt{x+3}=9x+8-\left(x+26\right)\sqrt{x-1}\)
g) \(\sqrt[3]{3x+1}+\sqrt[3]{5-x}+\sqrt[3]{2x-9}-\sqrt[3]{4x-3}=0\)
Rút gọn A = \(\left(\frac{x+2\sqrt{x}+4}{x\sqrt{x}-8}+\frac{x+2\sqrt{x}+1}{x-1}\right) :\left(3+\frac{1}{\sqrt{x}-2}+\frac{2}{\sqrt{x}+1}\right)\)
a, Rút gọn A b , Tìm x thỏa mãn A > 1 c,Tính A với \(x=\frac{\sqrt{4+\sqrt{3}}+\sqrt{4-\sqrt{3}}}{\sqrt{4+\sqrt{13}}}+\sqrt{27-10\sqrt{2}}\)\(A=\frac{\sqrt{x}+1}{3\left(\sqrt{x}-1\right)}\)
Giải PT :\(\sqrt{x+3-4\sqrt{x-1}}+\sqrt{x+8-6\sqrt{x-1}}=1\)
