Ta có: \(\dfrac{x+1}{4}=\dfrac{9}{x+1}\) \(\left(x\ne-1\right)\)
\(\Rightarrow\left(x+1\right)^2=36\)
\(\Rightarrow\left|x+1\right|=6\) \(\Leftrightarrow\left[{}\begin{matrix}x+1=6\\x+1=-6\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=5\\x=-7\left(loại\right)\end{matrix}\right.\)
Vậy \(x=5\)