Question

(x-y)²-4
9-(x-y)2
(x²+4)²-16x²
 

Answer 1

\(\left(x-y\right)^2-4=\left(x-y-2\right)\left(x-y+2\right)\)

\(9-\left(x-y\right)^2=\left(3-x+y\right)\left(3+x-y\right)\)

\(\left(x^2+4\right)^2-16x^2=\left(x^2-4x+4\right)\left(x^2+4x+4\right)=\left(x-2\right)^2\left(x+2\right)^2\)

Answer 2

\((X-y)^2-4=(x-y-2)(x-y+2)\)\((X^2+4)^2-16x^2=(x^2+4)^2-(4x)^2=(x^2+4-4x)(x^2+4+4x)\)

\(9-(x-y)^2=(3-x+y)(3+x-y)\)

 

Answer 3

a)(x-y)²-4=(x-y)²-2²=(x-y-2)(x-y+2)

b)9-(x-y)²=3²-(x-y)²=(3-x+y)(3+x-y)

c)(x²+4)²-16x²=(x²+4)²-(4x)²=(x²+4-4x)(x²+4+4x)=(x-2)²(x+2)²=(x²-2)²

Answer 4

\(\left(x-y\right)^2-4=\left(x-y-2\right)\left(x-y+2\right)\)

\(9-\left(x-y\right)^2=\left(3-x+y\right)\left(3+x-y\right)\)

\(\left(x^2+4\right)^2-16x^2=\left(x^2-4x+4\right)\left(x^2+4x+4\right)=\left(x-2\right)^2\cdot\left(x+2\right)^2\)