\(sinx.cos3x-sinx+2cos3x-2=0\)
\(\Leftrightarrow sinx\left(cos3x-1\right)+2\left(cos3x-1\right)=0\)
\(\Leftrightarrow\left(sinx+2\right)\left(cos3x-1\right)=0\)
\(\Leftrightarrow cos3x=1\)
\(\Leftrightarrow3x=k2\pi\)
\(\Rightarrow x=\dfrac{k2\pi}{3}\)
Do \(x\in\left(0;2\pi\right)\Rightarrow x=\left\{\dfrac{2\pi}{3};\dfrac{4\pi}{3}\right\}\)
\(\Rightarrow\dfrac{2\pi}{3}+\dfrac{4\pi}{3}=2\pi\)