Question

Tính:

\(\dfrac{-1}{3}.\dfrac{141}{17}-\dfrac{39}{3}.\dfrac{-1}{17}\)

Answer 1

Ta có: \(\dfrac{-1}{3}\cdot\dfrac{141}{17}-\dfrac{39}{3}\cdot\dfrac{-1}{17}\)

\(=\dfrac{-1}{3}\cdot\dfrac{141}{17}-\dfrac{-1}{3}\cdot\dfrac{39}{17}\)

\(=\dfrac{-1}{3}\cdot\left(\dfrac{141}{17}-\dfrac{39}{17}\right)\)

\(=\dfrac{-1}{3}\cdot6=-2\)