Question

Tính

x³-3x²+3x-1-8y³

^{Giúp mị vs!}

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Answer 1

\(x^3-3x^2+3x-1-8y^3=\left(x-1\right)^3-\left(2y\right)^3\)

=\(\left(x-1-2y\right)\left(\left(x-1\right)^2+2y\left(x-1\right)+4y^2\right)\)

=\(\left(x-2y-1\right)\left(x^2-2x+1+2xy-2y+4y^2\right)\)

Answer 2

\(x^3-3x^2+3x-1-8y^3\)

\(=\left(x-1\right)^3-\left(2y\right)^3\)

\(=\left(x-1-2y\right)\left(\left(x-1\right)^2+2xy+4y^2\right)\)