\(a.M_{th}\\ PTHH:2NaOH+SO_2\rightarrow Na_2SO_3+H_2O\\ n_{SO_2}=\frac{16,8}{22,4}=0,75\left(mol\right)\\ V_{NaOH}=\frac{n}{C_M}=\frac{0,75.2}{0,5}=3\left(l\right)\)
\(b.M_{axit}\\ PTHH:NaOH+SO_2\rightarrow NaHSO_3\\ n_{SO_2}=\frac{16,8}{22,4}=0,75\left(mol\right)\\ V_{NaOH}=\frac{n}{C_M}=\frac{0,75}{0,5}=1,5\left(l\right)\)
\(c.hh.2M\\ n_{Na_2SO_3}=x;n_{NaHSO_3}=y\\ PTHH:2NaOH+SO_2\rightarrow Na_2SO_3+H_2O\\ PTHH:NaOH+SO_2\rightarrow NaHSO_3\\ \sum n_{SO_2}=\frac{16,8}{22,4}=0,75\left(mol\right)\\ hpt:\left\{{}\begin{matrix}x+y=0,75\\\frac{x}{y}=\frac{2}{1}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=0,5\\y=0,25\end{matrix}\right.\\ V_{NaOH}=\frac{n}{C_M}=\frac{2x+y}{0,5}=2,5\left(l\right)\)
