\(P=\dfrac{\sin60^0+\tan^230^0}{\cos30^0-\cot60^0}=\left(\dfrac{\sqrt{3}}{2}+\dfrac{1}{3}\right):\left(\dfrac{\sqrt{3}}{2}-\dfrac{\sqrt{3}}{3}\right)\)
\(=\dfrac{3\sqrt{3}+2}{6}:\dfrac{3\sqrt{3}-2\sqrt{3}}{6}\)
\(=\dfrac{3\sqrt{3}+2}{\sqrt{3}}=\dfrac{6+2\sqrt{3}}{3}\)