\(4-x=2\left(x-4\right)^2\)
\(\Rightarrow4-x=2x^2-16x+32\)
\(\Rightarrow2x^2-15x+28=0\)
\(\Rightarrow2x\left(x-4\right)-7\left(x-4\right)=0\)
\(\Rightarrow\left(x-4\right)\left(2x-7\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=4\\x=\dfrac{7}{2}\end{matrix}\right.\)