\(4x-3-x-5=30-3x\)
\(4x-x+3x=30+3+5\)
\(6x=38\)
\(x=\dfrac{38}{6}\)
\(\Rightarrow4x-3-x-5=30-3x\)
\(\Rightarrow6x=38\)
\(\Rightarrow x=\dfrac{19}{3}\)
Vậy....
\(=>4x-3-x-5=30-3x\)
\(=>3x-8=30-3x\)
\(=>3x+3x=30+8\)
\(6x=38=>x=\dfrac{38}{6}=\dfrac{19}{3}\)